<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3
x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405
</span>
</span>
</span>
<span>
x2 = </span><span><span><span>-0.404072
</span>
</span>
</span>
Answer:
16.C
17.20
Step-by-step explanation:
16.Add 8+5=13
17.Add 12+8=20
Let x=papers on Saturday and y=papers on Sunday
First make equations for the information given to you
x+y=52 (total papers) and y= x+8 (he sold 8 more on Sunday)
then since you know y=x+8 then substitute it in the other equation like so
x+(x+8)=52 which means 2x+8=52 which means 2x=44 and therefore x=22
the problem however asks for sunday and not saturday, so solve for y now
y=x+8 which means y=22+8 which means y=30
He sold 30 papers on Sunday
If it's a six sided dice, then it would be 1 out of 3.
I hope that helped :)
