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BigorU [14]
3 years ago
7

Find the solution set of the inequality

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer: x>- 7/3


Step-by-step explanation:

Solve for x by simplifying bot sides of the equation, then isolating the variable.

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What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal
rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0
3 years ago
Ations with the Distributive Property<br> Solve the equation.<br> -3(y + 5)= 15
AlekseyPX
Y=-3 it is the answer.
6 0
4 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
Elden [556K]

Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

                                                                  Head          Tail

 P(E1)= 1/2  ----------          Coin 1               H,H              T,H

                                                                1/4                  1/4

  P(E2)= 1/2  ---------------  Coin 2             H, H               H,T

                                                                      1/4           1/4

So the events are independent.

The probability of showing heads on both toss is equal to 1/2

The sample space for this experiment consists of 2⁴= 16 sample points, out of which eight will have heads on both toss.

Or in other words ( 1/4* 1/4) = 2/4 = 1/2

4 0
3 years ago
What is the ratio of total shapes to triangles? Circle ⭕ triangle triangle circle ⭕ triangle triangle circle ⭕ triangle triangle
olya-2409 [2.1K]
3:2. There's a total of 9 shapes, 6 triangles, and 3 circles. 
Next, you take the ratio of 9:6 and divide each number by 3, one at a time.
6 0
3 years ago
Solve the following problem.
Serggg [28]
<span>It costs 19.48, because $16,421.40 / 843 comes out to 19.479, and 19.479 rounds to 19.48. So the answer is B $19.48.

Hope this helps :)</span>
8 0
3 years ago
Read 2 more answers
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