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BigorU [14]
3 years ago
7

Find the solution set of the inequality

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer: x>- 7/3


Step-by-step explanation:

Solve for x by simplifying bot sides of the equation, then isolating the variable.

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3s+2p=85.50 4s+2p=123
Gala2k [10]

Answer:s=10.50 and p=27

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP!!!!!!!!!!!!
Igoryamba
<h3>Answer:  21x+14  (choice A)</h3>

Explanation:

Use the distribution rule to multiply the outer 7 by each term inside

  • 7 times 3x = 21x
  • 7 times 2 = 14

We go from 7(3x+2) to 21x+14

3 0
2 years ago
Read 2 more answers
Cynthia Besch wants to buy a rug for a room
77julia77 [94]

The length and width of the rug is 20 and 11 feet respectively

The given parameters;

dimension of the room = 19 ft by 28 ft

maximum area of rug she can afford = 220 ft²

For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y

(28-2x)(19-2x)=220

532-94x+4x^2=220

4x^2-94x+312=0

x=39/2,4

For x=39/2, dimensions are negative.

The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11

Thus, the dimensions of the rug should be 20 feet and 11 feet

  • The area of a rectangle is length times breadth.
  • Area is the total squares cm occupied by a closed figure.

To learn more about area of a rectangle visit:

brainly.com/question/20693059

#SPJ9

6 0
1 year ago
What is this value 4.6(-2)
Bingel [31]

Answer:

-9.2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?
Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

  • Substitute the values

{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

5 0
3 years ago
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