Answer:s=10.50 and p=27
Step-by-step explanation:
<h3>
Answer: 21x+14 (choice A)</h3>
Explanation:
Use the distribution rule to multiply the outer 7 by each term inside
- 7 times 3x = 21x
- 7 times 2 = 14
We go from 7(3x+2) to 21x+14
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
-9.2
Step-by-step explanation:
<h2><u>Diagram</u><u>:</u><u>-</u></h2>
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
The diagonals of the Rhombus= d1 & d2=6cm and 8cm
Let the Side=a
As we know that in a Rhombus
<h2>_____________</h2><h3>Again </h3>
we know that in a Rhombus
Perimeter of the rectangle is 20cm.
