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ahrayia [7]
3 years ago
9

If a gas at 35.0 °C is pressurized from 160 kPa to 250 kPa, determine the final temperature of the gas. Assume the volume and am

ount of gas are held constant. Show your work. please help
Chemistry
1 answer:
Zanzabum3 years ago
6 0
This problem is a simple application of Gay-Lussac's Law for gases.

Gay - Lussac's Law states that the pressure and temperature (in absolute scale) of a gas are proportional.

This is:

p / T = constant => p1 / T1 = p2 / T2.

Here you have p1 = 160 kPa; T1 = 35.0 + 273.15 = 308.15 K; p2 = 250 KPa; T2 = ?

Then, just solve T2 from the equation above.

T2 = p2 * T1 / p1 =   250 kPa * 308.15K / 160 kPa = 481.48 K.

T2 = 481.48 - 273.15 = 208.33 °C.

Answer: 208.33 °C.


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