Answer:
P1V1/T1= P2V2/T2
Explanation:
Combined gas law involves Boyle's law and Charles law altogether with the formula of Boyle's law as P1V1=P2V2
formula for charles law as V1/T1=V2/T2
so when combined form P1V1/T1=P2V2/T2
make or become hot or warm is heating.
cooling is to become colder or cool down from a higher temp.
The question is incomplete, complete question is:
Study this chemical reaction:
Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
Oxidation:
Reduction:
Answer:
Oxidation taking place in given reaction :
Reduction taking place in given reaction;
Explanation:
Redox reaction is defined as the reaction in which oxidation and reduction reaction occur side by side.
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
In the given reaction, iron(II) ions are getting reduced and zinc metal is getting oxidized to zinc(II) ions.
Oxidation :
Reduction ;
Answer:
a)23.2 L
b)68.3kPa
c)7.5 atm
d)60.5L
e)1.67 atm
Explanation:
From Boyle's law:
P1V1=P2V2
P1= 748mmHg
P2=725mmHg
V1= 22.5L
V2??
V2= P1V1/P2= 748×22.5/725= 23.2 L
b)
V1=4.0L
P1= 205×10^3Pa
V2= 12.0L
P2=???
P2= P1V1/V2= 205×10^3×4/12
P2= 68.3×10^3 Pa or 68.3kPa
c)
P1= 1 atm
V1= 196.0L
P2= ??
V2= 26.0L
P2= P1V1/V2=1×196.0/26.0
P2= 7.5 atm
d)
V1= 40.0L
P1= 12.7×10^3Pa
V2=???
P2= 8.4×103Pa
V2= P1V1/P2= 12.7×10^3×40.0/8.4×103
V2=60.5L
e)
V1= 100mL
P1= 1atm
V2= 60mL
P2=???
P2= P1V1/V2= 1×100/60
P2= 1.67 atm
The answer <span>is <span>8.9 g/mL</span>.</span>
The density (D) is <span>equal to mass (m) divided by volume (V): D = m/V
Let's find the mass of the object:
m = 156 g - 105.5 g = 50.5 g
Let's find the volume of the volume:
V = 30.7 mL - 25 mL = 5.7 mL
The density is:
D = m/V = 50.5 g / 5.7 mL = 8.9 g/mL</span>
