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mina [271]
3 years ago
5

What's the word of a theory that states that earths crust and upper mantle are broken into sections which move around on a speci

al layer of the mantle?
Chemistry
2 answers:
zaharov [31]3 years ago
5 0
The Plate Tectonic Theory
stiv31 [10]3 years ago
4 0

Answer:

The Plate Tectonic theory

Explanation:

According to the theory of plate tectonics, the earth's lithosphere is comprised of numerous plates which are commonly known as tectonic plates and are mainly of two types, the continental and oceanic crust.

These plates move over a relatively less dense layer of asthenosphere where the rocks flow in response to deformation. This movement of plates is due to the formation of convection current in the mantle and this currents are formed because of the heat supplied from the interior of the earth.

This is the main driving force for the lithospheric plates to move over the layer of asthenosphere.

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Explanation:

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Answer:

Bohr model A

Explanation:

It has more valance electrons therefore has more interaction between the atoms and has more electronegativity.

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27Hq)+3816(7/ 23q09)
8 0
2 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
Which is the stronger acid in each of the following pairs? Explain your reasoning.
Makovka662 [10]

Answer:p-hydroxybenzaldehyde is stronger acid to phenol

para-cyanophenol is stronger acid to meta-cyanophenol

o-fluorophenol is stronger acid to p-fluorophenol.

Explanation:

The PKa tool relative to Ph are used to contrast the pairs.

The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24

The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95. 

The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature

The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.

6 0
3 years ago
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