Because its structure is drawn by dots which can't describ its structure.
The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is

=

. We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.
Answer:
a. True
b. False
c. True
d. False
e. False
Explanation:
A. (true) The equilibrium constant K is defined as
In any case
aA +Bb ⇌ Cd +dD
where K is:
![K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D)
A large value on K means that the concentration of products is bigger than the concentrations of reagents, so the forward reaction is favored, and the equilibrium lies to the right.
B. (False) When we work with gases, we use partial pressure to make calculations in the equilibrium, so we estimate Kp as:

Using the ideal gas law, we can get a relationship between K and Kp
Pv=nRT where
we know that
is the molar concentration. When we replace P in the expression for Kp we get:
![Kp= \frac{[C]^{c}*(RT)^{c}[D]^{d}*(RT)^{d}}{[A]^{a}*(RT)^{a}[B]^{b}*(RT)^{b}}](https://tex.z-dn.net/?f=Kp%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%2A%28RT%29%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%2A%28RT%29%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%2A%28RT%29%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%2A%28RT%29%5E%7Bb%7D%7D)
Reorganizing the equation:
![Kp= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}*\frac{(RT)^{c+d}}{(RT)^{a+b}}](https://tex.z-dn.net/?f=Kp%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D%2A%5Cfrac%7B%28RT%29%5E%7Bc%2Bd%7D%7D%7B%28RT%29%5E%7Ba%2Bb%7D%7D)
We can see K in the expression
Delta n = c+d-a-b
For the reaction

Delta n = 2-1-1=0
So Kp=K in this case.
C. (true) The value of K just depends on the temperature that’s why changing the among of products won’t have any effect on its value.
D. (false) as we can see this reaction involve a heterogeneous system with solids and gases. For convention the concentration for solids and liquids can be considered constant during the reaction that’s why they’re not include in the calculation for the equilibrium constant. Taking this into account the expression for the equilibrium for this reaction is:
So we can see that
is not include in the expression.
E. (False) The equilibrium is defined as the point where the rate of the forward reaction is the same to the rate of the reverse reaction. The value of K is telling you which reaction is favored but the rate of both reactions is the same in this point. (see picture)