Question

2x-4y=2 -2x+3y=0 elimination

Answer 1

$2x-4y=2 \\ \underline{-2x+3y=0} \\ -4y+3y=2+0 \\ -y=2 \\ y=-2 \\ \\ 2x-4y=2 \\ 2x-4 \times (-2)=2 \\ 2x+8=2 \\ 2x=2-8 \\ 2x=-6 \\ x=\frac{-6}{2} \\ x=-3 \\ \\ (x,y)=(-3,-2)$

Answer 2

2x-4y=2

-2x+3y=0

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3y-4y=2

-y=2   /*(-1)

y=-2

2x-4y=2

2x-4*(-2)=2

2x+8=2   /-8

2x=-6

x=-3