-4(2y)+11y=15, -8y+11y=3y=15: y=5
X=2(5)=10
To check your work -4(10)+11(5)=15
15=15
Answer:
2.92 × 10⁹
Step-by-step explanation:
im not exactly sure if im right but this is what i know, lmk if its wrong
Answer:
Step-by-step explanation:
Let the other side of the rectangle be y. The perimeter of the rectangle is expressed as P = 2(x+y)
Given P = 30ft, on substituting P = 30 into the expression;
30 = 2(x+y)
x+y = 15
y = 15-x
Also since the area of the rectangle is xy;
A = xy
Substitute y = 15-x into the area;
A = x(15-x)
A = 15x-x²
The function that models its area A in terms of the length x of one of its sides is A = 15x-x²
The side of length x yields the greatest area when dA/dx = 0
dA/dx = 15-2x
15-2x = 0
-2x = -15
x = -15/-2
x = 7.5 ft
Hence the side length, x that yields the greatest area is 7.5ft.
Since y = 15-x
y = 15-7.5
y = 7.5
Area of the rectangle = 7.5*7.5
Area of the rectangle = 56.25ft²
Answer:
A quadratic equation is some thing like
(x+2)^2
or
(x+2)(x+5)
In order to solve them, the most basic method is the FOIL method
F-First
O-Outside
I-Inner
L-Last
So for example
(x+2)^2
Which is basically
(x+2)(x+2)
So the first is the 2 Xs
(x+2)(x+2)
x*x=x^2
The outer is the x and the 2,
(x+2)(x+2)
2*x=2x
Now the Inner which is the 2 and the x
(x+2)(x+2)
2*x=2x
And finally the last which is the 2 and the second 2
(x+2)(x+2)
2*2=4
Now add them all up
X^2+2x+2x+4
Combine like terms
x^2+4x+4
There you have it
Do the same with every other quadratic equation
