The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
An easy way is to do it, if you get confused by multiplying fractions, is by turning the fractions into decimals. Since you are trying to find N you want to multiply the 1/5 by the 1/3.
1/5 = 0.2
1/3 = 0.33333333333333333333333333333333
if you multiply those you get 0.06666666666666666666666666666667 which when put into a fraction it equals 1/15
but if you don't want to do that just try to remember that you want to get by itself. and when multiplying fractions in this situation the bottom numbers only matter.. so 5 x 3 = 15 1/15
would you like me to put it in a document to show you?
The answer is 573
S is the three digit number.
h - a number of hundreds
t - a number of tens
o - a number of ones
S = 100h + 10t + o
<span>The last two digits add to make ten: t + o = 10
</span><span>The first and last digits add to make eight: h + o = 8
</span><span>The first two digits add to make twelve: h + t = 12
</span>t + o = 10 ⇒ o = 10 - t
h + o = 8 ⇒ o = 8 - h
_______
10 - t = 8 - h
h + t = 12 ⇒ h = 12 - t
_______
10 - t = 8 - (12 - t)
10 - t = 8 - 12 + t
10 - t = -4 + t
10 + 4 = t + t
2t = 14
t = 14/2 = 7
______
h = 12 - t = 12 - 7 = 5
______
o = 8 - h = 8 - 5 = 3
S = 100h + 10t + o
h = 5
t = 7
o = 3
S = 100*5 + 10*7 + 3
= 500 + 70 + 3
= 573
Answer:
3sqrt(2)
Step-by-step explanation:
sqrt(32) - sqrt(2)
rewriting sqrt(32)
sqrt(16*2) - sqrt(2)
sqrt(16) * sqrt(2) - sqrt(2)
4 sqrt(2) - sqrt(2)
3sqrt(2)
