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3 years ago

5. Janet has 5 marbles. She finds double that number of marbles in her art box. How many marbles does Janet have now?

Mathematics

2 answers:

JulijaS [17]3 years ago

8 0

She has 10 marbles, because 5*2 =10 marbles.

Alexeev081 [22]3 years ago

4 0

Janet has 10. How you solve this problem is 5 x 2 because it is doubled.

Your welcome :)

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Please help!!!!!!! I only have 20 minutes left!!

slavikrds [6]

Step-by-step explanation:

You need to find the total number of students the pie chart will represent:

17 + 35 + 38 = 90

So you know, 360° represents 90 people

You can then find out the angle for each person: 360 ÷ 90 = 4

Each person is 4°

1. 17 people took French so you would do 4° × 17 = 68°

2. 35 people took German so you would do 4° × 35 = 140°

3. 38 people took Italian so you would do 4° × 38 = 152°

17 out of 90 people chose french so the probability would be 17/90

5 0

2 years ago

You can walk 3 miles per hour, jog 5 miles per hour, or run 10 miles per hour. You go a full hour before changing pace. At the e

Studentka2010 [4]

Answer:

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22) 199

Step-by-step explanation:

a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.

Thus, the number of ways one can cover n miles will be given by the recurrence relation

p(n) = p( n-3) + p( n-5) + p( n - 10)

now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.

check the attachment for the table

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22) 199

8 0

2 years ago

A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet

gregori [183]

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662 $μm^{2}$ .