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Misha Larkins [42]
3 years ago
12

How do I solve these problems?

Mathematics
1 answer:
topjm [15]3 years ago
8 0
6) 18,26,34
Add 8 each time
… 42,50,58,66,74,82,90,98,106,114,122,130
The 15th term in the sequence would be 130
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the second term in a geometric sequence is 12. the fourth term in the same sequencce is 4/3. what is the common ratio in this se
nordsb [41]
Geo is
an=a1r^(n-1)

2nd term is 12
4th term is 4/3

a2=a1r^(2-1)=12
a2=a1r=12

a4=a1r^(4-1)=4/3
a4=a1r^3=4/3

we have
a1r=12 and a1r^3=4/3
(a1r^3)/(a1r)=r^2=(4/3)/12=1/9

1/9=r^2
sqrt oth sides
1/3=r

the common ratio is 1/3
5 0
4 years ago
Adult tickets to a basketball game cost 5$. Student tickets cost 1$. A total of 2,874$ was collected on the sale of 1,246. How m
Karolina [17]
2,874 divided by 5 = 574.8
Since we know anything divided by 1 is that number.
We do 2,874 - 574.8 = 2,299.2
This is how we get our answer.

So,574.8 of the 1,246 tickets were Adult tickets and 2,299.2 tickets were student tickets.
8 0
3 years ago
Perform the indicated operation (3 - 5i) - (-2 +11i)​
dalvyx [7]

Answer:

5 - 16i

Step-by-step explanation:

combine like terms:

3 - (-2) = 5

(-5i) - 11i = -16i

<em>5 - 16i</em>

<em></em>

7 0
3 years ago
Find the product of (3x − 4)(2x2 + 2x − 1).
STALIN [3.7K]

the answer to your question is -12





5 0
3 years ago
Read 2 more answers
8x +2 factored using the GCF
wolverine [178]

The answer is 2 because I solved it and checked it.


7 0
3 years ago
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