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yaroslaw [1]
3 years ago
14

13 dollars to 15 percent

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
4 0

Answer:

$1.95 is 15% of 13 dollars

valentinak56 [21]3 years ago
4 0

Answer:

13 - 15% (1.90) = 11.10

Step-by-step explanation:

13 - 15% (1.90) = 11.10

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Which strategy would not correctly solve this story problem? Jason bought a bagel and a cup of coffee each Saturday. Each bagel
snow_tiger [21]
This answer is not correct

<span>C. Use objects to model the problem. Take 8 pieces of play money. Take away 1 piece for the coffee and 2 pieces for the bagel.</span>
8 0
3 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u &gt; 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
2 years ago
At 8:00 a.m., there were t inches of snow on the ground. At 5:00 p.m., there were 3t inches of snow on the ground. How many more
Anastaziya [24]

we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

3t- t = 2t

And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

t = (12in)/3 = 4 in

Replacing that in the difference of heights:

2t = 2*4in = 8in

From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

If you want to learn more about linear equations:

brainly.com/question/1884491

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3 0
2 years ago
Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).
3241004551 [841]

You did not provide us with equations to select.

Find the slope m.

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m = -1/(3 + 1)

m = -1/4

Use the slope and one of the points and plug into the point-slope formula.

y - 1 = (-1/4)(x - 3)

Isolate y.

y - 1 = (-1/4)x + (3/4)

y = (-1/4)x + (3/4) + 1

y = (-1/4)x + (7/4)

Did you follow?

5 0
3 years ago
Read 2 more answers
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alexira [117]

Answer:

radius 2

Step-by-step explanation:


8 0
3 years ago
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