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3 years ago

If an ips identifies an attack, it can ________.

Computers and Technology

1 answer:

Gennadij [26K]3 years ago

5 0

Answer:

a. drop the attack packet(s)

Explanation:

An IPS not only detects and alerts system administrators but it also stops attacks. It is built to consistently monitor a network, report malicious incidents and take preventative actions. So, how does an IPS work exactly? An IPS does a deep packet inspection and either blocks the IP of whoever sent the malicious packet or removes the malicious packet's content and repackages its payloads. Thus, this means that the malicious packet is completely dropped by stripping off of its header information and any infected items in the packet.

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To create a formula in______, you would first click in one of the cells

Pavlova-9 [17]

Answer:excel

Explanation:

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4 years ago

Read 2 more answers

The source ip address is 164.109.28.3 subnet mask of 255.255.128.0 network address is

Sergeu [11.5K]

164.109.0.0/17

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6 0

3 years ago

Computer Networks - Queues

lyudmila [28]

Answer:

the average arrival rate \lambda in units of packets/second is 15.24 kbps

the average number of packets w waiting to be serviced in the buffer is 762 bits

Explanation:

Given that:

A single channel with a capacity of 64 kbps.

Average packet waiting time $T_w$ in the buffer = 0.05 second

Average number of packets in residence = 1 packet

Average packet length r = 1000 bits

What are the average arrival rate \lambda in units of packets/second and the average number of packets w waiting to be serviced in the buffer?

The Conservation of Time and Messages ;

E(R) = E(W) + ρ

r = w + ρ

Using Little law ;

r = λ × T_r

w = λ × T_w

r / λ = w / λ + ρ / λ

T_r =T_w + 1 / μ

T_r = T_w +T_s

where ;

ρ = utilisation fraction of time facility

r = mean number of item in the system waiting to be served

w = mean number of packet waiting to be served

λ = mean number of arrival per second

T_r =mean time an item spent in the system

T_w = mean waiting time

μ = traffic intensity

T_s = mean service time for each arrival

the average arrival rate \lambda in units of packets/second; we have the following.

First let's determine the serving time T_s

the serving time T_s $= \dfrac{1000}{64*1000}$

= 0.015625

now; the mean time an item spent in the system T_r = T_w +T_s

where;

T_w = 0.05 (i.e the average packet waiting time)

T_s = 0.015625

T_r = 0.05 + 0.015625

T_r = 0.065625

However; the mean number of arrival per second λ is;

r = λ × T_r

λ = r / T_r

λ = 1000 / 0.065625

λ = 15238.09524 bps

λ ≅ 15.24 kbps

Thus; the average arrival rate \lambda in units of packets/second is 15.24 kbps

b) Determine the average number of packets w waiting to be serviced in the buffer.

mean number of packets w waiting to be served is calculated using the formula

w = λ × T_w

where;

T_w = 0.05

w = 15238.09524 × 0.05

w = 761.904762

w ≅ 762 bits

Thus; the average number of packets w waiting to be serviced in the buffer is 762 bits

4 0

3 years ago

JAVA PROGRAMMING

VashaNatasha [74]

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class GtldValidation {

public static void main (String [ ] args) {

Scanner scnr = new Scanner(System.in);

// Define the list of valid core gTLDs

String [ ] validCoreGtld = { ".com", ".net", ".org", ".info" };

// FIXME: Define an array named validRestrictedGtld that has the names

// of the restricted domains, .biz, .name, and .pro

String [] validRestrictedGtld={".biz",".name",".pro"};

String inputName = "";

String searchName = "";

String theGtld = "";

boolean isValidDomainName = false;

boolean isCoreGtld = false;

boolean isRestrictedGtld = false;

int periodCounter = 0;

int periodPosition = 0;

int i = 0;

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

while (inputName.length() > 0) {

searchName = inputName.toLowerCase();

isValidDomainName = false;

isCoreGtld = false;

isRestrictedGtld = false;

// Count the number of periods in the domain name

periodCounter = 0;

for (i = 0; i < searchName.length(); ++i) {

if (searchName.charAt(i) == '.') {

++periodCounter;

periodPosition = i;

}

// If there is exactly one period that is not at the start

// or end of searchName, check if the TLD is a core gTLD or a restricted gTLD

if ((periodCounter == 1) &&

(searchName.charAt(0) != '.') &&

(searchName.charAt(searchName.length() - 1) != '.')) {

isValidDomainName = true;

}

if (isValidDomainName) {

// Extract the Top-level Domain name starting at the period's position. Ex:

// If searchName = "example.com", the next statement extracts ".com"

theGtld = searchName.substring(periodPosition);

i = 0;

while ((i < validCoreGtld.length) && (!isCoreGtld)) {

if(theGtld.equals(validCoreGtld[i])) {

isCoreGtld = true;

}

else {

++i;

}

// FIXME: Check to see if the gTLD is not a core gTLD. If it is not,

// check to see whether the gTLD is a valid restricted gTLD.

// If it is, set isRestrictedGtld to true

}

System.out.print("\"" + inputName + "\" ");

if (isValidDomainName) {

System.out.print("is a valid domain name and ");

if (isCoreGtld) {

System.out.println("has a core gTLD of \"" + theGtld + "\".");

}

else if (isRestrictedGtld) {

System.out.println("has a restricted gTLD of \"" + theGtld + "\".");

}

else {

System.out.println("does not have a core gTLD."); // FIXME update message

}

else {

System.out.println("is not a valid domain name.");

}

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

}

return;

}

8 0

3 years ago

Write commands to carry out the following commands: a) Print all lines containing the string John. b) Print all lines where a wo

egoroff_w [7]

Answer:

see explaination

Explanation:

1. grep 'John' FileName

2. grep '^\J' FileName

3. grep 'stopped$' FileName

4. grep -v -e 'was' FileName

5. grep -E '^(k|K)' FileName

#print the message to create subdirectory

echo "Creating a subdirectory to copy current directory files into named 'sub'"

#create subdirectory

mkdir sub

echo "Directory successfully created"

#Copy the files in the current working directory to created subdirectory

echo "Copying files of current directory into newly created subdirectory"

rsync -a --exclude='sub' * sub

#display the message to copy the files

echo "Copying operation completed successfully"

echo "Now deleting the created subdirectory along with its contents"

rm -rf sub

#indicated the message completion of task

echo "Operation completed successfully."

#prompt and read the first number

echo "Enter the first number: "

read x

echo "Enter the second number: "

read y

#Compute arithmetic operations and store in the

#respective variable

addition=$(($x + $y))

subtraction=$(($x - $y))

multiplication=$(($x * $y))

division=$(($x / $y))

#print the values

echo "Addition of $x and $y is $addition"

echo "Subtraction of $x and $y is $subtraction"

echo "Multiplication of $x and $y is $multiplication"

echo "Division of $x and $y is $division"

3 0

3 years ago