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Luda [366]
3 years ago
15

Which statement is true about the geometric figure that can contain these points

Mathematics
1 answer:
Rashid [163]3 years ago
6 0

Answer:

One plane can be drawn so it contains all three points.

Step-by-step explanation:

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A credit card has an annual percentage rate of 23 988% the balanced owed is $1450.00. Assuming no additional charges are made. W
tatyana61 [14]
The answer should be 120.83
8 0
2 years ago
PLEASE HELP - image attachment below, thanks! :)
CaHeK987 [17]
32 as well according to some rule in geometry
8 0
1 year ago
Read 2 more answers
Compare and Contrast Graph y = 2x + 5 and y=-13x+5. Describe how these lines are alike and how they are different. *​
krek1111 [17]

Here are a couple I found:

<u>Similarities</u>:

  • They have the same y-intercept of (0,5).
  • They are both in slope-intercept form.

<u>Differences</u>:

  • The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
  • They have different x-intercepts. (y = 2x + 5 intersects (-\frac{5}{2}, 0) while y = -13x + 5 intersects at (\frac{5}{13}, 0)

<u></u>

<u>Explanation</u>:

Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).

As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.

4 0
2 years ago
In Maria's physics class, she had to solve the equation 5=12at2+ut+x for u.
olasank [31]

Answer:

u= 5/t-12at-x/t

Step-by-step explanation:

I dont know what youre asking but that is the solved equation

7 0
3 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
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