What is the solution to 3|x + 3| = 12?

Which of the following weights would you expect to be suitable for weighing on an ordinary bathroom scale?

Ierofanga [76]

Answer:

c) $4.10^{6} cg$ =40Kg

Step-by-step explanation:

To find the answer we have to put all the options in the same unit, so we are going to use Kg.

a) 2500 μg

μ $=1.10^{-6}$

Replacing the value of μ:

$2500.1.10^{-6} g=\\ 2500.10^{-6} g$

Observation: 1 g = 0.001 Kg, 1 g= $1.10^{-3}$ Kg

$2500.10^{-6} g=\\ =2500.10^{-6}.10^{-3}Kg\\=2500.10^{-9}Kg$

$2500.10^{-9}Kg=0.000002500 Kg$

This number is very small so it's no suitable for weighing on an ordinary bathroom scale.

b) $5.10^{-4}Kg$

This value is already in kilograms,

$5.10^{-4} kg=0,0005 Kg$

But it's small. It's not suitable for weighing on an ordinary bathroom scale.

c) $4.10^{6} cg$

Centigrams: cg= $1.10^{-5} Kg$

Then,

$4.10^{6} cg=4.10^{6}.10^{-5}Kg\\ =4.10^{1} Kg\\ =40 Kg$

This value it's suitable for weighing on an bathroom scale.

d) $5,5.10^{8} dg$

Decigrams: dg= $1.10^{-4} Kg$

Then,

$5,5.10^{8} dg=5,5.10^{8}.10^{-4}Kg\\ =5,5.10^{4} Kg\\ =55000 Kg$

This value is too big for a bathroom scale. Usually the limit for an ordinary bathroom scale is between 140-150 Kgs.

e) $2,0.10^{7} mg$

Miligrams: mg= $1.10^{-6} Kg$

Then,

$2,0.10^{7} mg=2,0.10^{7}.10^{-6}Kg\\ =2,0.10^{1} Kg\\ =20 Kg$

This could be a right answer too but it all depends on the scale. There are some scales whose minimum weight is 30Kg. So the right answer is c)

5 0

4 years ago

Given the Arithmetic sequence A1,A2,A3,A4 44, 51, 58, 65 What is the value of A39?

snow_lady [41]

This is an arithmetic sequence because there is a common difference between terms, a constant found when subtracting the preceding term from any term in the sequence. In this case the common difference is 7.

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial value, d=common difference, n=term number

Here we have a=44 and d=7 so

a(n)=44+7(n-1)

a(n)=44+7n-7

a(n)=7n+37, so the 39th term is:

a(37)=7(37)+7

a(37)=266

I am assuming that 44 is the first term, not the 5th term...if 44 was the fifth term let me know and I will edit to reflect that...

6 0

3 years ago

Read 2 more answers

Find the value of x such that 3^(x^2)/ (3^(2x))=27

cestrela7 [59]

This is how this one is done. I'm assuming by this type of a problem that you are in logs in math since you need to rules of logs to solve it. First things first...laws of exponents when the bases are like. Our base is a 3. Here's the problem written out: $\frac{3^ x^{2} }{3 ^{2x} } =27$ . The rules for exponents when dividing like bases is that you subtract the exponents. So we will do that: $3^{x^2-2x} =27$ . Since we are solving for x we need to find a way to get it down from its exponential position. We do that by takking the log of both sides. $log 3^{x^2-2x}=log27$ . Another rule of logs, the power rule, is that once we take the log of a base with an exponent, we can move the exponent down in front, like this: $x^2-2x[log(3)]=log27$ . Now we will divide both sides by log(3) to get $x^2-2x= \frac{log(27)}{log(3)}$ . We do that math on the right side on our calculator to get $x^2-2x=3$ . Now this is something we can handle. We have a second degree polynomial that we have to factor for x. Do that by moving the 3 over by subtraction. $x^2-2x-3=0$ . Factoring that you have that x = 3 and x = -1. There you go!

4 0

3 years ago

Select all ratios equivalent to 1:2. is it 10:20. 7:14. 6:18.

Alex787 [66]

10:20 I think if it isn’t I’m sorry

6 0

3 years ago

Read 2 more answers

When setting up a proportion to calculate scale drawings, how do you write the proportion? A)actual/actual B)actual/drawing C) d

Semmy [17]

When setting up a proportion to calculate scale drawings, how do you write the proportion? A)actual/actual B)actual/drawing C) drawing/drawing D)drawing/actual

The correct answer is option D: drawing/actual

Suppose there is a drawing that has a scale of 1:10. So, this means anything drawn with the size of "1" would have an actual size of "10" in the real world, so a measurement of 120mm on the drawing would be 1200mm on the actual/real image.

3 0

4 years ago