You dont have anything that we can answer to.
Answer:
ddddddddddddddddddddddddddddddddddddd
Step-by-step explanation:
ddddddddddddddddddddddddddddddddddddd
Answer:
11253
Step-by-step explanation:
the steps are described in the picture above
For A. the muddy water will slowly begin to decrease because it's been left out in the sun, some of the water will begin to evaporate.
(I don't know about B, or C, but I tried my best on A.)
Make sure to put in your own words. :)
Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
