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Nat2105 [25]
3 years ago
10

The volume of the rectangular box shown below is 96. If the base of the box has the dimensions shown, what is the height of the

box?​

Mathematics
1 answer:
Georgia [21]3 years ago
7 0

Answer:

he volume of a rectangular object is defined as

Volume = base*height*width

In the picture below, we can see that the base is denoted as x , the height is denoted as y and the width is denoted as z

Volume = x*y*z

96 = x*y*z

Since there is no more information on the problem, we can find the height of the box in terms of the other two variables (width and base)

y = 96/(x*z)

height = Volume/(base*width)

Step-by-step explanation:

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icang [17]

Answer:

31.5 or 63/2

Step-by-step explanation:

to do this, first you need to transform the <u>mixed number</u> <em>(3 1/2)</em> into an <u>improper fraction</u>, to get 7/2.

then you just multiply 9 by 7/2

9/1 (7/2)

63/2 = 31.5

<em>both of the answers in bold are correct</em>

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20

Step-by-step explanation:

20 is divisible by 4, 5 and 10

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Read 2 more answers
Find the distance from point A(−1, 7) to the line y=3x. Round your answer to the nearest tenth.
bearhunter [10]

Answer:

<em>The distance from the point to the line is approximately 3.2 units</em>

Step-by-step explanation:

<u>Distance From a Point to a Line</u>

Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.

If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is

\displaystyle d= \frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}

The line is given by the equation:

y=3x. We need to transform it into the specified form.

Subtracting 3x:

y - 3x = 0

Comparing with the general form of the line, we have

a=-3, b=1, c=0

The point (xo,yo) is (-1,7), thus:

\displaystyle d= \frac{|-3\cdot (-1)+1\cdot 7+0|}{\sqrt{(-3)^2+1^2}}

\displaystyle d= \frac{|3+7|}{\sqrt{9+1}}

\displaystyle d= \frac{|10|}{\sqrt{10}}

\displaystyle d= \frac{10}{\sqrt{10}}

d\approx 3.2

The distance from the point to the line is approximately 3.2 units

4 0
3 years ago
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