Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
Answer:
It will be biased.
Step-by-step explanation:
By surveying only grades 1, 2, and 3, she is not taking a representation of the entire school. It is possible that the popular color or the color the students like would change over time and the opinion of the younger kids could be different from that of the older kids. Therefore, the sample is biased unless she surveys students from all grades.
<h3>
Answer: 19</h3>
Explanation:
Let's break 110 down into its prime factors
110 = 11*10
110 = 11*2*5
110 = 2*5*11
We have three different prime factors that multiply to 110. However, the instructions say there are 4 integers that multiply to 110. To fix this, we can say
110 = 1*2*5*11
now we see that 1,2,5 and 11 multiply out to 110
They add to 1+2+5+11 = 3+16 = 19
Answer:
multiply by 2
Step-by-step explanation:
