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3 years ago

What is the GCF of 36 and 84

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

3 0

The greatest common factor( GCF) of 36 and 84 is 12.

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Two circles have the same radius. Complete the description for whether the combined area of the two circles is the same as the a

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Answer:

A1=2π*r^2

A2=π(2r)^2=4π*R^2

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3 years ago

Easy question Trolls will be reported<br>What is the inverse of the following statement?<br><br>

timama [110]

Answer: if a/b =/ c, then a =/ bc.

Step-by-step explanation:

inverse means to negate, so if somethings positive you need to change it to negative

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3 years ago

Please help!<br> Solve for x.

aalyn [17]

Answer:

1. 15.9

2. 12

3. 7.29

4. 20.8

5. 11.0

Step-by-step explanation:

We can use the Pythagorean Theorem to solve for x (a squared minus b squared equals c squared)

Example number 1 is solved by 17 squared - 6 squared equals 253

You do square root and get 15.90

Number 4 is you have to divide 24 by 2 because it is one of the sides

So it is 24 squared minus 12 squared

You find square root and get 20.80

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3 years ago

Oliver deposits $1,000 in his Interest-bearing bank account. The balance increases by %15 each month

Volgvan

Step-by-step explanation:

Oliver deposits P= $1,000

Then total amount A after n months given that the balance increases by %15 each month can be calculated as

$A= 1000(1+15/100)^n$

Assuming the increase in amount is compounded monthly.

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3 years ago

A rectangle is constructed with its base on the x-axis and two of its vertices on the parabola y equals = 100 100 minus −x squa

masha68 [24]

Answer:

Step-by-step explanation:

Given that a rectangle is constructed with its base on the x axis and two of its vertices on the parabola

$y=100-x^2$

This parabola has vertex at (0,100) and symmetrical about y axis.

Any general point above x axis can be written as (a,b) (-a,b) since symmetrical about yaxis.

Hence coordinates of any rectangle are

$(a,0) (-a,0), (a, 100-a^2), (-a, 100-a^2)$

Length of rectangle = 2a and width = $100-a^2$

Area of rectangle = lw = $2a(100-a^2)=200a-400a^3$

To find max area, use derivative test.

$A' = 200-800a^2\\A"=-1600a$

Hence maxima when first derivative =0

i.e. when a =2

Thus we find dimensions of the rectangle are l =4 and w = 96

Maximum area = $4(96) = 384$

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3 years ago