3 years ago

Caroline receives $80 for her birthday

1 answer:

ella [17]3 years ago

3 0

That alone of money I ant liying

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MrRissso [65]

Answer: The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

Step-by-step explanation:

Given : A kite is being flown at $45^{\circ}$ . The string of the kite is 120 feet long.

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

$\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}$

hence, The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

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lions [1.4K]

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