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Scorpion4ik [409]

3 years ago

6

The x-intercepts of the parabola (y = 2x^2 + 13x - 7) are at (p,0) and (q,0). Find p and q. Enter your answer in the form "p, q"

.

2 answers:

Kobotan [32]3 years ago

7 0

Answer:

-7 and 0.5

Step-by-step explanation:

pantera1 [17]3 years ago

7 0

Vivuvtc yy. CBC ttv gghvn

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Pls help, will give brainlist if u give me the answer!!

timama [110]

Answer:

$7.5 plus $65 per hour

Step-by-step explanation:

We are trying to find the minimum she can make in one day. The minimum amount of hours she can work is 1, so find y when x=1:

y=7.5x+65

y=7.5(1)+65

y=7.5+65

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3 years ago

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Degger [83]

If her hourly rate stays the same, how many hours would she have<span> to work to earn $217 next week? ... She wants to enlarge the </span>photograph<span> so that its </span>width<span> is 10 in. ... Cross-Multiply: (4)(x)=(6)(10); Simplify: 4x=60; Divide both sides by 4 to find the height of the </span>new photograph<span>: \frac{4x}{4}=\frac{60}{4. Answer: 15 </span>inches<span> .</span>

8 0

3 years ago

Can anybody help with this one ...... ?

VLD [36.1K]

Answer:The answer is choice 3

Step-by-step explanation:

8 0

3 years ago

Dmitry [639]

Answer:

y = 5

Step-by-step explanation:

if y = 5 then

(√10-1) -1 = 2

3 - 1 = 2

true

5 0

3 years ago

Read 2 more answers

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

<em>0.12 = Speed of water being pumped -6.8 </em>

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

2 years ago