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Vinil7 [7]
4 years ago
11

What is the solution to the equation? 98 + g = 150 98 + g = 150. 98 + 98 + g = 150 minus 98. t = 52. 98 + g = 150. 98 minus 98 +

g = 150 minus 98. t = 52. 98 + g = 150. 98 + 98 + g = 150 + 98. t = 52. 98 + g = 150. 98 minus 98 + g = 150 + 98. t = 148.
Mathematics
1 answer:
masha68 [24]4 years ago
7 1

Answer:

The solution to the question is g = 52

Step-by-step explanation:

Here, we want to find the solution to the equation ;

98 + g = 150

Apparently, we want to find the value of g.

To get the value of g, what we simply need is to bring 98 over the equal sign and this gives

g = 150-98

g = 52

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Answer:

The standard deviation is 0.4984 \hbar

Step-by-step explanation:

In order to find standard deviation, The equation is given as

\sigma=\sqrt{\frac{1}{n} \sum_{i=1}^{100} (\mu-x_i)^2

Here μ is the mean which is calculated as follows

                                       \mu=\frac{\sum_{i=1}^{100} x_i}{n}\\\mu=\frac{46\times \frac{\hbar}{2}+54\times \frac{-\hbar}{2}}{100}\\\mu=\frac{-4 \hbar}{100}\\\mu=-0.04 \hbar

Now the standard deviation is given as

                      \sigma=\sqrt{\frac{1}{100} \sum_{i=1}^{100} (-0.04 \hbar-x_i)^2}\\\sigma=\sqrt{\frac{1}{100} [[46 \times(-0.04 \hbar-0.5 \hbar)^2]+[54 \times(-0.04 \hbar+0.5 \hbar)^2]}]\\\sigma=\sqrt{\frac{1}{100} [[46 \times(-0.54 \hbar)^2]+[54 \times(0.46 \hbar)^2]}]\\\sigma=\sqrt{\frac{1}{100} [[46 \times(0.2916 \hbar)]+[54 \times(0.2116 \hbar)]}]\\\sigma=\sqrt{\frac{1}{100} [13.4136 \hbar+11.4264 \hbar}]\\\sigma=\sqrt{\frac{24.84 \hbar}{100}}\\\sigma =0.4984 \hbar

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4 0
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(6,-2)

Step-by-step explanation:

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Hope this helped you :)

3 0
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Which ordered pairs in the form (x,y) are solutions to the equation 7 x - 5y = 28?
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Answer:

C

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