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Mamont248 [21]
3 years ago
13

The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x

Mathematics
1 answer:
Marianna [84]3 years ago
7 0
<span>You can use Heron's formula to solve this problem.

</span>A= \sqrt{s(s-a)(s-b)(s-c)} , where A is the area; a,b,с are the sides;  s<span> is the </span>semiperimeter<span> of the triangle
</span>s= \frac{a+b+c}{2}

<span>According to conditions:
</span>a = x
b = x+1
с = 2x-1

<span>Calculate the semiperimeter:
</span>s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x

<span>Now we can compose and solve the equation according to Heron's formula:
</span>\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10}   \\  \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\  \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\  \sqrt{2x^3-2x^2}=x \sqrt{10}  \  \  \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\  \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6

<span>As a result, x = 6 is your answer.
 
I hope this helped.</span>
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