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ELEN [110]
4 years ago
15

What are the bugs that make noises in the trees

Physics
2 answers:
aksik [14]4 years ago
7 0

Answer:

the answer is cicadas.

Explanation:

They are very noisy insects and I've seen one make noises in my tree

Sedaia [141]4 years ago
7 0

Answer:

Cicadas are the bugs that make noises in trees. Cicadas have a special organ called a tymbal that produces sound. The tymbal contains a series of ribs that buckle one after the other when the cicada flexes its muscles. Every time a rib buckles, the rib produces a click.

Please rate me brainliest! :D

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If an object accelerates from rest, with a constant acceleration of 4.4 m/s2, what will its velocity be after 28s?
Norma-Jean [14]

Answer:

123.2 m/s after 28s

Explanation:

Vi= 0 m/s

a= 4.4 m/s^2

t=28s

Vf after 28s

To find Vf use your kinematics formula Vf=Vi+at

Vi is Zero so it gets removed and the equation becomes

Vf=at  

Simply Plug and Solve

Vf= 4.4(28)

Vf=123.2 m/s after 28s

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A thermometer is placed directly sunlight will it read the temperature of the air or of the sun or of something else??
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It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
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Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the melting of ice, and expla
BlackZzzverrR [31]
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Read 2 more answers
Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N
Simora [160]

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, F_f, backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

F-F_f = 0\\F_f = F = 1850 N

The frictional force can be written as

F_f = \mu R (1)

where

\mu is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

R = W = mg

where

m = 520 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

Substituting into (1),

F_f = \mu mg = 1850 N

and solving for \mu,

\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

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brainly.com/question/2235246

#LearnwithBrainly

5 0
4 years ago
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