All categories

3 years ago

Is the time in Tennessee the same as florida

Physics

2 answers:

n200080 [17]3 years ago

7 0

Florida is in US/Eastern time while Tennessee is in US/Central time, which is about an hour difference.

geniusboy [140]3 years ago

5 0

I would say the same thing as the first answer

You might be interested in

A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 40 m/s when i

Alenkinab [10]

Given that,

Initial velocity , Vi = 0

Final velocity , Vf = 40 m/s

Acceleration due to gravity , a = 9.81 m/s²

Distance can be calculated as,

2as = Vf² - Vi²

2 * 9.81 *s = 40² - 0²

s = 81.55 m

For half height, that is, s = 40.77m

Vf= ??

2as = Vf² - Vi²

2 * 9.81 * 40.77 = Vf² - 0²

Vf² = 800

Vf = 28.28 m/s

Therefore, speed of roller coaster when height is half of its starting point will be 28 m/s.

5 0

3 years ago

Which of these is NOT a chemical property of matter?

marshall27 [118]

C. Magnetism

It is a physical property, not a chemical property.

7 0

2 years ago

Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law

ehidna [41]

Answer:

hi iam 8 and a girl your hot

Explanation:

7 0

3 years ago

When a lorge heavy truck collieds with a

arsen [322]

Yes since the heavy truck it’s way bigger it can cause more damage to the passenger car

7 0

3 years ago

Two forces are acting on an object. The first force has magnitude F1=33.4 N and is pointing at an angle of θ1=23.8 clockwise fro

marishachu [46]

Answer:

Fe= 28.2 N : Magnitude of the equilibrant (Fe)

β = 18.34° , clockwise from the positive x axis

Explanation:

Concept of the equilibrant

It is called equilibrant to a force with the same magnitude and direction as the resulting one (in case it is non-zero) but in the opposite direction. Adding vectorially to all the forces (that is to say the resulting one) with the equilibrant you get zero

To solve this problem we decompose the forces given into x-y components to find the resulting force:

Look at the attached graphic

F₁= 33.4 N , θ₁=23.8° clockwise from the positive y axis (y+)

F₁x= 33.4 *sin23.8° = 13.48 N

F₁y= 33.4 *cos23.8° =30.6 N

F₂=46.1 N , θ₂=28.8 counterclockwise from the negative x axis (x-)

F₂x= -46.1 *cos28.8° = -40.4 N

F₂y= -46.1 *sin28.8° = -22.2 N

Components of the resultant in x-y R(x,y)

Rx= 13.48 N -40.4 N = - 26.92 N

Ry= 30.6 N -22.2 N = + 8.4 N

Components of the equilibrant in x-y Fe(x,y)

Fex= +26.92 N

Fey= - 8.4 N

Magnitude of the equilibrant (Fe)

$F_{e} = \sqrt{(F_{ex})^{2}+{(F_{ey})^{2} }$

$F_{e} = \sqrt{(26.92)^{2}+(8.4)^{2} }$

Fe= 28.2 N

Angle the equilibrant makes with the x axis ( β)

$\beta = tan^{-1} (\frac{F_{ey} }{F_{ex} } )$

$\beta = tan^{-1} (\frac-8.4 }{26.92 } )$

β = -18.34°

β = 18.34° , clockwise from the positive x axis

8 0

3 years ago