The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;

<u>For </u><u>student 1</u><u>:</u>

Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>

Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
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Answer:
1.7531 smu/yn
Explanation:
check the attached file below for answer and explanation.
The acceleration of the object which moves from an initial step to a full halt given the distance traveled can be calculated through the equation,
d = v² / 2a
where d is distance, v is the velocity, and a is acceleration
Substituting the known values,
180 = (22.2 m/s)² / 2(a)
The value of a is equal to 1.369 m/s²
The force needed for the object to be stopped is equal to the product of the mass and the acceleration.
F = (1300 kg)(1.369 m/s²)
F = 1779.7 N
The correct answer is this one: "length of address." The element that is not part of Aristotle's rhetorical triangle is the length of the address. The rhetorical triangle of Aristotle are the logos, pathos, and ethos. Logos is the logic, Pathos is the audience emotion, Ethos is the speaker's credibility.
From Ohm's law: R = V / I
Resistance = (voltage) / (current)
The first paragraph TELLS you that the current is always 0.5 A, and the table tells you the voltage across each piece of wire.
Again . . . <em>R = V / I</em>