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3 years ago

Identify the equation in point slope form for the line parallel to y=1/2x-7 that passes through (-3,-2)

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

5 0

The answer to the question

sleet_krkn [62]3 years ago

4 0

Parallel lines have the same slope.

We have $y=\dfrac{1}{2}x-7$ .

Therefore we have $y=\dfrac{1}{2}x+b$

We must find b. We know, the line passes through (-3, -2).

Substitute the values of point to the equation of the new function:

$-2=\dfrac{1}{2}(-3)+b\\\\-2=-1.5+b\qquad|\text{add 1.5 to both sides}\\\\-0.5=b\to b=-0.5\to b=-\dfrac{1}{2}$

Answer: $y=\dfrac{1}{2}x-\dfrac{1}{2}$

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There are 4 red golf balls and 2 green golf balls in a bucket. You select a ball at random, keep it, and select again. Find the

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3 years ago

Read 2 more answers

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

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3 years ago

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Citrus2011 [14]

Answer) -5/2 quarts per hour
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