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avanturin [10]
3 years ago
15

Solve and show steps please please please I NEED HELP ASAP ILL MARK AS Brainlsit plsss

Mathematics
1 answer:
Rainbow [258]3 years ago
5 0
ANSWER : x>-2


Subtract one from both sides
-3x < 6
Divide both sides by negative 3
-3x/3 < 6/-3

Then you get the answer x>-2
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Ron finds 9 books at a bookstore that he would like to buy, but he can afford only 5 of them. In how many ways can he make his s
olga55 [171]

Answer:

d. 126; 70

Step-by-step explanation:

given that Ron  finds 9 books at a bookstore that he would like to buy, but he can afford only 5 of them.

Out of 9 books he has to select 5 of them

Here selection of books can be done in any order.  Hence order does not matter

No of ways he selects 5 books out of 9 books = 9C5

= 126

Part II

One book is a must

Hence he has options only 4 books from the remaining 8.

No of ways when one book is compulsory = selecting 3 books from 8 books

= 8C4

= 70

Option d is right.

6 0
3 years ago
a pipe is leaking at 1.5 cups per day. about how many gallons per week is the pipe leaking? (HINT : 1 gallon = 16 Oz) 
Basile [38]
.65625 gallons per week
tht ur answer
3 0
3 years ago
1 - (8 to the second power + 6)<br><br> Which do I do first 8+6 the then exponent or Vice versa?
Svet_ta [14]
You would need to do it vice versa
6 0
3 years ago
Read 2 more answers
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
What is the product a2/5 (10)?
melisa1 [442]
The correct answer is 2a^2
8 0
3 years ago
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