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Vera_Pavlovna [14]
3 years ago
12

Four and one-half minus three and five-eighths

Mathematics
1 answer:
Leni [432]3 years ago
4 0
4 1/2-3 5/8=0.875 or 875/1000 or 35/40 or 7/8
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Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.
vesna_86 [32]
Perpendicular has the reciprocal slope and u have to put the point given into point slope.

y-3=9/2(x-4)

(The slope of the original equation was -2/9)
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Can someone ONE person tutor me in math?plsss
Rina8888 [55]

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I can

Step-by-step explanation:

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25 POINTS!! HELP ASAP PLEASE!!!
gladu [14]

Answer:

b.

Step-by-step explanation:

Stem is the first digit and the leaf is the last digit.

Below the table is explained that 1 l 7 is 1.7 because it also could mean 17. So with that clear the terms from the Stem l Leaf are as follow:

1 combined with 3, 7 and 7:

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2 combined with 6, 8 and 8:

2.6, 2.8, 2.8

3 combined with 5 and 7:

3.5 and 3.7

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1.3, 1.7, 1.7, 2.6, 2.8, 2.8, 3.5, 3.7

4 0
3 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
Distributive prperty m(13-2r)
exis [7]

Answer:

13m-26mr boom that's it

Step-by-step explanation:

i think

5 0
3 years ago
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