Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer:
4 units
Step-by-step explanation:
i hope its right
Answer: (a) $6,600
(b) $28,600
<u>Step-by-step explanation:</u>
Interest (I) = Principal (P) x rate (r) x time (t)
I = 22,000(0.06)(5)
= 6,600
Accrued (A) = Principal (P) + Interest (I)
A = 22,000 + 6,600
= 28,600
Answer:C =$65 + $30G
Step-by-step explanation:
Given that :
Base fee charge = $65
Overage charge = $30 / per gigabyte for data that exceeds 2 gigabyte
C = cost ; G = total amount of gigabyte
Equation to represent plan; if more than 2 gigabyte are used :
Cost (C) = Base charge + (average charge * amount of gigabyte)
C = $65 + ($30 * G)
C =$65 + $30G
