Question

What is the solution set to.the following system?{x+y=4, x^2+y^2=16}

Answer 1

Answer:

x= 3.47 or x= -4.47 ,  y= 0.53 or y= 8.47

Step-by-step explanation:

quadratic equation:

x^2 + y^2 = 16

(-b± √b^2 - 4*a*c) /2

(-1 ± √ 1-4*1*16)/2

(-1 ± 3√7)/2

(-1 ± 7.94)/2

(-1 + 7.94 )/2 or (-1-7.94)/2

x= 3.47 or -4.47

therefore:

x+y = 4

3.47 + y = 4     or -4.47 + y = 4

y = 4-3.47       or y = 4+ 4.47

y= 0.53   or y = 8.47