Center of circle is ( 1, 0).
Slope of normal passing though ( 1, 0 ) and ( 2, -5 ) is :
So, slope of tangent will be :
Equation of tangent :
Hence, this is the required solution.
Solve(4/x)-(2/5)=(6/x)
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Center of circle is ( 1, 0).
Slope of normal passing though ( 1, 0 ) and ( 2, -5 ) is :
So, slope of tangent will be :
Equation of tangent :
Hence, this is the required solution.