Assuming that the equation defines x and y implicitly as differentiable functions xequals=f(t), yequals=g(t), find the slope o
f the curve xequals=f(t), yequals=g(t) at the given value of t. x^3+3t^2 =13, 2y^3−3t^2= 42, t=2. The slope of the curve at t=2 is what?
1 answer:
Answer:

Step-by-step explanation:
Given that x and y are implicitly as differentiable functions.
xequals=f(t), yequals=g(t),


we have to get value of x and y at t =2

we have to find the slope of the curve at t=2
i.e. we have to find 
=
at t=2


Substitute the values of x and y and also t in these equations to get

Slope = 
You might be interested in
Answer:
35
Step-by-step explanation:
35 is exactly 152 but since its asking for greater then you're right it is 36.
But since it says '>' it means not equal to so it would be:
x > 35
or
x ≥ 36
Answer:
a=-2
Step-by-step explanation:
5 go to another side by negative sign
and the coefficients of a will added
-16=8a
8 go to the other side
a=-2
Answer:
dog
Step-by-step explanation:
Answer:
-216 is the answer