Please help!!

Triangle ABC is similar to triangle PQR, as shown below:

natita [175]

Answer:

$\frac{q}{b}=\frac{r}{c}$

Step-by-step explanation:

Consider the options for this question are as follow,

$\frac{q}{c}=\frac{r}{b}$

$\frac{c}{p}=\frac{b}{a}$

$\frac{c}{a}=\frac{q}{r}$

$\frac{q}{b}=\frac{r}{c}$

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

$\traingle ABC\sim \triangle PQR$

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

$\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}$

$\frac{c}{r}=\frac{a}{p}=\frac{b}{q}$

$\frac{r}{c}=\frac{p}{a}=\frac{q}{b}$

$\implies \frac{q}{b}=\frac{r}{c}$

3 0

3 years ago

Read 2 more answers

In △ABC, D is a point on side AC¯¯¯¯¯¯¯¯ such that BD=DC and ∠BCD measures 70∘. What is the degree measure of ∠ADB?

777dan777 [17]

If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.

Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer

5 0

3 years ago

Complete the table by filling in the elapsed tine.<br> Help pls

Sav [38]

Answer:

RADIUS

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PROBLEM

Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?

SOLUTION

We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.

\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr

\tt{226.08 = 2(3.14) r}226.08=2(3.14)r

'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.

\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

226.08=2(3.14)r

6.28

226.08

=

6.28

6.28r

C=36

To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

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#CarryOnLearning

7 0