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3 years ago

So I need some help please

Mathematics

1 answer:

Assoli18 [71]3 years ago

4 0

Answer:

Sorry but i can't see the choices.

Step-by-step explanation:

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A candy maker buys a bar of chocolate weighing 162 oz. About how many lb does the bar weigh?

Natali [406]

Use dimensional analysis. 1 lb = 16 oz will be the conversion factor. 162 oz x (1 lb/16 oz) = 10.125 lb.

7 0

2 years ago

Read 2 more answers

Craig’s Kimbrell of the Atlanta braves, can throw his fast ball at 102 miles per hour. Convert this rate to feet per second

omeli [17]

Firstly, you change it to miles per second and then to feet
102miles per hour(60×60s)
102 per 120s
Divide
102÷120
=0.85miles per second
Convert to feet
=4488 feet per second

6 0

3 years ago

Which of the following is equivalent to 2 ln e^ln 5x = 2 ln 15?

neonofarm [45]

Answer:

x = 3

Step-by-step explanation:

Given in the question an equation,

$2lne^{ln5x}=2ln15$

Step 1

$e^{lnx}=x$

so,

$2ln(5x)=2ln15$

Step 2

cancel 2 on both sides of the equation

$ln{5x}=ln15$

Step 3

$ln{5x}-ln15=0$

$ln\frac{5x}{15}=0$

Step 4

$ln\frac{x}{3}=0$

Step 5

$e^{ln\frac{x}{3}}=e^{0}$

Step 6

x/3 = 1

x = 3(1)

x = 3

8 0

2 years ago

I NEED HELP WITH MATH !!!

Mademuasel [1]

Ok cccccccccccccccccccccc

4 0

3 years ago

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If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

2 years ago