The answer would be 3 because 3✖️4= 12
4c + 5h = 650 and
5c + 6h = 800 where c are chefs, h are helpers
Start by finding an expression for c
4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4
Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50
Take that 50 and substitute it into the expression we have for c to get a number value for c
C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100
Check your first equations, substituting $50 for the helpers and $100 for the chefs.
4 (100) + 5(50) =
400 + 250 = 650
5(100) + 6(50) =
500 + 300 = 800
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Answer:
Jānis Čakste
Step-by-step explanation:
Ohhhh nasty ! What a delightful little problem !
The first card can be any one of the 52 in the deck. For each one ...
The second card can be any one of the 39 in the other 3 suits. For each one ...
The third card can be any one of the 26 in the other 2 suits. For each one ...
The fourth card can be any one of the 13 in the last suit.
Total possible ways to draw them = (52 x 39 x 26 x 13) = 685,464 ways.
But wait ! That's not the answer yet.
Once you have the 4 cards in your hand, you can arrange them
in (4 x 3 x 2 x 1) = 24 different arrangements. That tells you that
the same hand could have been drawn in 24 different ways. So
the number of different 4-card hands is only ...
(685,464) / (24) = <em>28,561 hands</em>.
I love it !
