Answer:
so
slope is calculated this way:
let's calculate y init by:
3 = -3×2 + b
b = 9
so equation is:
y=-3x+9
Answer
Find out the m∠6 .
To prove
As given
a∥e , m∥n , and m∠2 = 112°.
As m∥n
a is the transversal (A line that cuts across two or more (usually parallel) lines is called transverasl.)
Thus
∠ 2 = ∠3 ( Corresponding angle property )
∠3 = 112°
Also
a∥e and m is transversal .
∠ 3 = ∠6 = 112 ° ( Corresponding angle property )
Therefore
∠6 = 112°
Answer:
Step-by-step explanation:
Suppose the base formula is y = x^2
You want to go two units left.
basically that is y = (x + 2)^2 just the opposite of what you might think it should be.
Where does the base function have a minimum? It's minimum is as x = 0 and y = 0
Where does y = (x + 2)^2 have it's minimum?
(-2,0)
conclusion. The base function has moved 2 units to the left.
If you were to write it fully, as an equation, I believe it would look like this:
x²(4x-x) *4x
Therefore allowing you to simplify the area within the bracket into:
x²(3x)*4x
To expand, you simply start on the left and work your way across.
3x³*4x= 12x⁴
