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navik [9.2K]
3 years ago
8

What’s the distributive property for 3(2x -1)*

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0

Answer:

6x-3

Step-by-step explanation:

remove breceket

3×2 =6

3×-1= -3

answer is 6x-3

Ede4ka [16]3 years ago
3 0
6x=3 is the answer.
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Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. each pot cost $0.25 more than the next one below
Svetllana [295]
1. Do 8.25-3.75=4.5 because 3.75 is the total amount added onto the price of the flower pots from the base price
2. Do 4.5/6=.75 because you have 6 of the base price added into the total cost
3. Do .75+1.25=2 because of the .25 added with every pot
So the price of the largest pot is 2
6 0
3 years ago
A company has determined that it must increase production of a certain line of goods by 112 times last years production. The new
liraira [26]

Answer: 26 items

Step-by-step explanation:

Let x denotes the last year's output.

Given : A company has determined that it must increase production of a certain line of goods by 112 times last years production.

The new output will be 2885 items.

According to the above statement we have the following equation :-

112x=2885

Divide both sides by 112, we get

x=25.7589285714\approx26

Hence, the  last year's output =26 items

3 0
4 years ago
P;EASE HELP!!!!!  Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end
Marrrta [24]
<span>The end behavior of a polynomial function is the behavior of the graph of f as 
x → +∞ or x → -∞ , depending on its leading coefficient.

In the example, the LEADING COEFFICIENT = - 3x</span>⁵
<span>,when x → +∞, ( - 3x⁵ ) → - ∞ . The end behavior, the polynomial approches minus infinity



</span>
7 0
4 years ago
Consider the surface given by
Mazyrski [523]
This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4 
    2x^2 + 5y^2 = 1.75
    Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
    5y^2 + z^2 = 2
    Now you have an ellipse in the x=1 plane as your trace.


(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
    2x^2 + 5y^2 = 4
    Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
    2x^2 + z^2 = 4
    Now you have an ellipse in the y=0 plane as your trace.


5 0
4 years ago
Find the probability of the indicated event if P(E) = 0.25 and P(F) = 0.40.
Wewaii [24]

Answer:

P(E\ or\ F) = 0.60

Step-by-step explanation:

Given

P(E) = 0.25

P(F) = 0.40

P(E\ and\ F) = 0.05

Required

Determine P(E or F)

This is calculated using:

P(E\ or\ F) = P(E) + P(F) - P(E\ and\ F)

P(E\ or\ F) = 0.25 + 0.40 - 0.05

P(E\ or\ F) = 0.60

4 0
3 years ago
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