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Romashka [77]
3 years ago
6

Solve the following system by any method. -8x -8y = 0 -8 + 2y = -20

Mathematics
1 answer:
professor190 [17]3 years ago
3 0
Hello!

First you have to find either x or y

We can use the second equation to find y

-8 + 2y = -20

Add 8 to both sides

2y = -12

Divide both sides by 2

y = -6

We can plug -6 in for y in the other equation

-8x - 8(-6) = 0

-8 * -6 = 48

-8x + 48 = 0

subtract 48 from both sides

-8x = -48

divide both sides by -8

x = 8

So the answers are x = 8 and y = -6

Hope this helps!
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HELP❤️❤️What are the solutions to the equation f(x) = g(x)
raketka [301]
The answer is B. 

If you look for where the two graphs intersect, you'll see that the x values of the ordered pairs are -4 (for the intersection in quadrant 2) and roughly 2.5 (for the intersection in quadrant 4). This problem is just asking you to look for those values. 
5 0
3 years ago
-4x-2y=30<br> 1/3y=7/3x+5/3<br> we are supposed to use substitution when solving
seropon [69]

Answer:

The solution set is (-20/9, -95/9)

Step-by-step explanation:

To solve using the substitution method, start by solving the second equation for y.

1/3y = 7/3x + 5/3

y = 7x + 5

Now that we have this, we can plug it in for y in the first equation. Then we can solve for x.

-4x - 2(7x + 5) = 30

-4x - 14x - 10 = 30

-18x - 10 = 30

-18x = 40

x = -20/9

Now that we have the value of x, we can solve for y by inputting the x value into either equation.

-4x - 2y = 30

-4(-20/9) - 2y = 30

80/9 - 2y = 30

80/9 - 2y = 270/9

-2y = 190/9

y  = -95/9

4 0
3 years ago
What does y equal in the equation -9y +19= -5x
MakcuM [25]
The answer is y=5x+19/9
8 0
3 years ago
Read 2 more answers
The average weight of an almond is 1,200 milligrams. You buy 65 almonds at the price of $0.10 per gram. How much do you pay for
Mademuasel [1]
1,200*65:1000=78 gram
78*0.10=7.8
You pay $7.8 for the 65 almonds
8 0
3 years ago
Which equation has x=-6 as the solution? A-logx36=2. B-log3(2x-9)=3. C-log3 216=x. D-log3(-2x-3)=2
bezimeni [28]
I posted this to your other question as well:

So we have:

A) \log_x(36)=2

B) \log_3(2x-9)=3

C) \log_3(216)=x

D) \log_3(-2x-3)=2

We need to try x = –6 in each equation until we find a solution that makes both sides of the equation equal.

For A, this gives an undefined result. Logarithms are only defined for bases that are positive real numbers not equal to 1.

For B, this again gives an undefined result. The logarithm of a number is only defined when that number is a positive real number. It would be –21, which is undefined.

For C, we have a defined operation, but \log_3(216)=4.893 \neq -6.

Finally, for D, we have 

\log_3(-2(-6)-3)=2\\ \log_3(9)=2 \\ 3^2=9 \\ 9=9

This is true.
5 0
4 years ago
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