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3 years ago

12

Compute the exact value of the function for the given x-value without using a calculator. You must show your work for full credi

t. f(x) = 5x for x = 2

2 answers:

yKpoI14uk [10]3 years ago

8 0

F(2) = 5(2)
F(2) = 10

CaHeK987 [17]3 years ago

4 0

Evaluate 5 x where x = 2:5 x = 5×2
5×2 = 10:Answer: 10

You might be interested in

A kicker made 10 of his last 12 field goals. Predict about how many of his next 42 field goals the kicker will not make. Show yo

dimulka [17.4K]

The number of his next 42 field goals the kicker will not make will be 35.

<h3>What are ratio and proportion?</h3>

A ratio is a collection of ordered integers a and b represented as a/b, with b never equaling zero. A proportionate expression is one in which two items are equal.

A kicker made 10 of his last 12 field goals.

Predict the number of his next 42 field goals the kicker will not make will be

Let x be the number of his next 42 field goals the kicker will not make.

Then we have

x / 10 ≠ 42 / 12

x ≠ 35

More about the ratio and the proportion link is given below.

brainly.com/question/14335762

#SPJ1

4 0

2 years ago

**Solve by Elimination<br> 3 + 2x - y = 0<br> -3-7y = 10x<br> 7) x =<br> 8) y =

timofeeve [1]

Answer:

Explanation:

3 + 2x - y = 0
Or 2x - y = -3 (1)

-3-7y = 10x
Or -10x - 7y = 3 (2)

2x - y = -3 (1)
-10x - 7y = 3 (2)
———————

Multiply 5 to (1)

5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1

Plug y value in (1)

2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1

Therefore, x = -1 and y = 1

7 0

2 years ago

A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.

Fed [463]

Answer:

A) $a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

B) $a_{0} = a_{1} = 0$

C) for n = 2

$a_{2}$ = 1

for n = 3

$a_{3}$ = 3

for n = 4

$a_{4}$ = 8

for n = 5

$a_{5}$ = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be : $2^{n-2}$ strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

$a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

b ) The initial conditions

The initial conditions are : $a_{0} = a_{1} = 0$

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

$a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}$

for n = 2

$a_{2}$ = 1

for n = 3

$a_{3}$ = 3

for n = 4

$a_{4}$ = 8

for n = 5

$a_{5}$ = 19

7 0

3 years ago

Jackie has 1 6/12 pitchers of fruit juice. She and her friend drink 4/12 of a pitcher. How much fruit does Jackie have left?

goldfiish [28.3K]

Answer:

$1\frac{1}{6}\ pitchers\ of\ fruit\ juice$

Step-by-step explanation:

we know that

To find out how much fruit Jackie has left, subtract 4/12 from 1 6/12.

Convert mixed number to an improper fraction first

$1\frac{6}{12}=\frac{1*12+6}{12}=\frac{18}{12}\ pitchers\ of\ fruit\ juice$

so

$\frac{18}{12}-\frac{4}{12}=\frac{14}{12}\ pitchers\ of\ fruit\ juice$

convert to mixed number

$\frac{14}{12}=\frac{12}{12}+\frac{2}{12}=1\frac{1}{6}\ pitchers\ of\ fruit\ juice$

6 0

3 years ago

Sam cut a flat wooden board into fourths. He used three of the pieces as backgrounds for posters. He used equal pieces of the le

grandymaker [24]

To answer this question you would start with 1 whole piece and break it into 4 equal pieces. Each piece would be 1/4 of the original.

If you used 3 of these, you are left with 1/4.

Out of the 1/4 leftover, you create 5 equal-sized pieces.

1/4 divided by 5.
1/4 x 1/5 = 1/20 of the original board for each.

8 0

3 years ago