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Varvara68 [4.7K]
3 years ago
10

Find the area of the circle with the given diameter. Use 3.14 for π. Round to two decimal places.

Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Answer:

14.13 m^2

Step-by-step explanation:

Formula for area:

3.14*r^2

To find the radius(r), you do diameter(d)/2:

9/2=4.5

3.14*4.5^2=14.13 m2

Shalnov [3]3 years ago
6 0

Answer: 28.26

Step-by-step explanation:

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Find all solutions to the equation in the interval [0, 2īt).<br> 4) sin 2x = -sin x
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Answer:

x={0, 2pi/3, pi, 4pi/3}

Step-by-step explanation:

First, move sin x by adding sin x to both sides. sin 2x+ sin x = 0. Next using the double angle identity, sin 2x=2(sin x)(cos x), so 2(sin x)(cos x)+sinx=0. Factoring, sin x(2cos x +1)=0. Solving, sin x=0 and 2cos x +1 = 0, or cos x = -1/2.

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Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter
mezya [45]

Answer:

Dimensions: A=a\cdot b=256

Perimiter: P=2a+2b

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

A=a\cdot b=256

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

b=\frac{256}{a}

The function we want to optimize is the diameter.

We can express the diameter as:

P=2a+2b=2a+2*\frac{256}{a}

To optimize we can derive the function and equal to zero.

dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16

The minimum perimiter happens when both sides are of size 16 (a square).

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