Hey can anyone help me was this math problem 2+2?
2 answers:
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Answer:
Roger should place the base of ladder approximately 5.7 m away from base of building to reach the window.
Step-by-step explanation:
Given,
Length of ladder = 9 m
We have to find that how far Roger should place the base of ladder to reach the window.
Solution,
We have drawn the diagram for your reference.
Here the building, the ladder on leaning with land makes a right angle triangle.
Where the length of ladder is 'hypotenuse'.
Height of window from the ground is 'one side of the triangle'.
And distance from base of building to the ladder is 'another side of the triangle'.
So, according to Pythagoras theorem;
"In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of other two sides".
On framing in equation form, we get;
Where 'a' = 1st side of right triangle =7 m
'b' = 2nd side of right triangle
'c' = hypotenuse = 9 m
Now we put the given values and get;
Now taking square root on both side, we get;
Hence Roger should place the base of ladder approximately 5.7 m away from base of building to reach the window.
The function is
we use the vertex form of the quadratic equation
We have given a graph,
<h3>What is the vertex form of the quadratic equation?</h3>y = a(x - h)^2 + k.
Therefore the vertex of the given graph is
See the vertex at (-2, 5)
Since the general way to write the vertex is (h, k), we compare (h, k) to (-2, 5).
Now we have given that (-4,1) use this value in the above equation so we get,
Using the value of an in equation (1) we get,
Therefore the function is
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