Help me quick.............................

Explain why 0.4×10=4 helpppppppppppppp meeee

Anton [14]

4/10= 0.4

So if 0.4x10=4, That means that 4. Is 4/10 of 10.

6 0

3 years ago

The denominator of a fraction in the simplest form is greater than the numerator by 1. If 4 is added to the numerator, and 3 is

Fantom [35]

Answer:

Step-by-step explanation:

Let the original fraction is: x/ x-1

And we have that:

4 is added to the numerator => new numerator is: x+4
3 is subtracted from the denominator => new denominator is: x -1-3 = x -4

the fraction itself is increased by 2 $\frac{1}{6}$

<=> $\frac{x}{x-1} *2\frac{1}{6}$ = $\frac{x+4}{x-4}$

<=> $7x^{2} -70x +24 = 0$

Solve for X then we substitue into the original fraction

4 0

3 years ago

Determine the two positive integers each square root falls between.

sertanlavr [38]

Answer:

10. (5, 6)

11. (1, 2)

12. (7, 8)

13. (10, 11)

14. (27, 28)

15. (11, 12)

Step-by-step explanation:

If you're not familiar with the squares of small integers, your calculator can help you figure this.

10. √28 ≈ 5.291 . . . . between 5 and 6

11. √3 ≈ 1.732 . . . . between 1 and 2

12. √59 ≈ 7.681 . . . . between 7 and 8

13. √115 ≈ 10.724 . . . between 10 and 11

14. √772 ≈ 27.785 . . . . between 27 and 28

15. √140 ≈ 11.832 . . . . between 11 and 12

5 0

3 years ago

Use numerals instead of words. If necessary, use / for the fraction bar(s). A parabola is given by the equation y = x2 + 4x + 4.

Anarel [89]

Graph x2 = 4y and state the vertex, focus, axis of symmetry, and directrix.This is the same graphing that I've done in the past: y = (1/4)x2. So I'll do the graph as usual: The vertex is obviously at the origin, but I need to "show" this "algebraically" by rearranging the given equation into the conics form:x2 = 4y Copyright © Elizabeth Stapel 2010-2011 All Rights Reserved
(x – 0)2 = 4(y – 0)This rearrangement "shows" that the vertex is at (h, k) = (0, 0). The axis of symmetry is the vertical line right through the vertex: x = 0. (I can always check my graph, if I'm not sure about this.) The focus is "p" units from the vertex. Since the focus is "inside" the parabola and since this is a "right side up" graph, the focus has to be above the vertex.From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that 4p = 4, so p = 1. Then the focus is one unit above the vertex, at (0, 1), and the directrix is the horizontal line y = –1, one unit below the vertex.vertex: (0, 0); focus: (0, 1); axis of symmetry: x = 0; directrix: y = –1Graph y2 + 10y + x + 25 = 0, and state the vertex, focus, axis of symmetry, and directrix.Since the y is squared in this equation, rather than the x, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking y-values first and then finding the corresponding x-values for x = –y2 – 10y – 25:To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:y2 + 10y + 25 = –x 
(y + 5)2 = –1(x – 0)This tells me that 4p = –1, so p = –1/4. Since the parabola opens to the left, then the focus is 1/4 units to the left of the vertex. I can see from the equation above that the vertex is at (h, k) = (0, –5), so then the focus must be at (–1/4, –5). The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is 1/4 units to the right of the vertex. Putting this all together, I get:vertex: (0, –5); focus: (–1/4, –5); axis of symmetry: y = –5; directrix: x = 1/4Find the vertex and focus of y2 + 6y + 12x – 15 = 0The y part is squared, so this is a sideways parabola. I'll get the y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.y2 + 6y – 15 = –12x 
y2 + 6y + 9 – 15 = –12x + 9 
(y + 3)2 – 15 = –12x + 9 
(y + 3)2 = –12x + 9 + 15 = –12x + 24 
(y + 3)2 = –12(x – 2) 
(y – (–3))2 = 4(–3)(x – 2)Then the vertex is at (h, k) = (2, –3) and the value of p is –3. Since y is squared and p is negative, then this is a sideways parabola that opens to the left. This puts the focus 3 units to the left of the vertex.vertex: (2, –3); focus: (–1, –3)

6 0

3 years ago

What is the amplitude of the graph of

Lera25 [3.4K]

It is 2 :)
Y=A sin(B(x+C))+D

Where A is equal to the amplitude.

Would appreciate brainliest answer :)

4 0

3 years ago