Let P be the population proportion, p be the sample proportion, n be the sample size.
A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06
Sample size n=97 and sample proportion p=0.05
The hypothesis to be tested is
H0: P ≥ 0.06 V/s Ha: P < 0.06
Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by
Z = 
Where p =sample proportion = 0.05
p0 = hypothesized proportion value =0.06
Using given values into test statistics we get
Z = 
Z = -0.41
The p-value for left tailed alternative hypothesis is given by
P-value = P(z < z cal)
where zcal = Z test statistics value
Here zcal = -0.41
P-value = P(Z < -0.41)
Using z score table to find probability below z=-0.41
P-value = 0.3409
P-value for testing the given claim is 0.3409
S(n)=^2
S(13), n=13
S(13)= (13)^2
(13)^2=169
Answer:
here is the answer
Step-by-step explanation:
hope it helps
Assume that 100% = 45 sales and 35% = X sales amount
You can create a ratio to help you solve for x
45 = 100%
x = 35 %
Which is equal to this fraction: (45/x) = (100/35)
Solving for X by cross multiplying and dividing by 100:
[(45)(35)] / 100 = X = 15.75 = 16 sales (rounded up)
You would need at least 16 sales to increase sales total by 35%
14. The distance between the two points is 14.866.
Distance can be calculated with the following formula:
d=√(x₂-x₁)²+(y₂-y₁)²
d=√(12-2)²+(5-(-6))²
d=√10²+11²
d=√100+121
d=√221
d=14.866
15. The distance between the two points is 20.248.
Use the same formula to find the distance.
d=√(x₂-x₁)²+(y₂-y₁)²
d=√(4-(-3))²+(12-(-7))²
d=√7²+19²
d=√49+361
d=√410
d=20.248