Answer: There are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.
There are 5 red fabrics and 11 gold fabrics that would be used for each curtain.
Step-by-step explanation:
Since we have given that
Number of yards of red fabric purchased by Jane = 50
Number of yards of gold fabric purchased by Jane = 110
We need to find the largest number of curtains she can make if she wants all the curtains to be exactly the same length.
For this we will find H.C.F. of 50 and 110.
Factors of 50 = 1, 2, 5, 10, 25, 50.
Factors of 110 = 1, 2, 5, 10, 11, 22, 55, 110.
So, Highest common factor of 50 and 110 is 10.
So, there are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.
Number of yards of red fabric is given by
Number of yards of gold fabric is given by
Hence, there are 5 red fabrics and 11 gold fabrics that would be used for each curtain.
<span>I will assume the more likely selection of $10 per sandal as opposed to $0.05 per sandal.
So with the formulas
c = 1000 + 5x
r = 75x - 0.4x^2
Sandals Cost Revenue Profit or Loss
0 $1,000.00 $0.00 -$1,000.00
1 $1,005.00 $74.60 -$930.40
2 $1,010.00 $148.40 -$861.60
3 $1,015.00 $221.40 -$793.60
4 $1,020.00 $293.60 -$726.40
5 $1,025.00 $365.00 -$660.00
6 $1,030.00 $435.60 -$594.40
7 $1,035.00 $505.40 -$529.60
8 $1,040.00 $574.40 -$465.60
9 $1,045.00 $642.60 -$402.40
10 $1,050.00 $710.00 -$340.00
11 $1,055.00 $776.60 -$278.40
12 $1,060.00 $842.40 -$217.60
13 $1,065.00 $907.40 -$157.60
14 $1,070.00 $971.60 -$98.40
15 $1,075.00 $1,035.00 -$40.00
16 $1,080.00 $1,097.60 $17.60
17 $1,085.00 $1,159.40 $74.40
18 $1,090.00 $1,220.40 $130.40
19 $1,095.00 $1,280.60 $185.60
20 $1,100.00 $1,340.00 $240.00
As you can see 16 sandals and up is profitable.
At what production levels will the company lose money?
a. between 0 and 10 or between 150 and 190 pairs, inclusive
150 and 190
c. between 10 and 20 or between 50 and 100, inclusive
If you add up the profit between 10 and 20 you will get $-484 so 50 and 100
b. between 0 and 15 or between 160 and 200 pairs, inclusive
160 and 200
d. between 15 and 35 or between 75 and 125, inclusive
Neither 15 and 35 or 75 and 125 will lose money.</span>
Answer:
7.30167%
Step-by-step explanation:
Usando la fórmula de puntuación z
z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población
Para x <0.20 pulgadas
z = 0.20 - 0.25 / 0.02
z = -2.5
Valor de probabilidad de Z-Table:
P (x <0.20) = 0.0062097
Para x> 0.28 pulgadas
z = 0.28 - 0.20 / 0.02
z = 1.5
Valor de probabilidad de Z-Table:
P (x <0.28) = 0.93319
P (x> 0.28) = 1 - P (x <0.28) = 0.066807
La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es
P (x <0.20) + P (x> 0.28)
= 0.0062097 + 0.066807
= 0.0730167
Conversión a porcentaje
= 0.0730167 × 100
= 7.30167%
El porcentaje de tornillos defectuosos producidos es
7.30167%
The square root of thirty lies between the numbers 5 and 6.
