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svet-max [94.6K]
3 years ago
8

Need help again, anyone??

Mathematics
2 answers:
stepladder [879]3 years ago
8 0

Rewrite B:  |x-3| - 1 = 5 becomes |x-3| = 6.  One way to interpret this follows:

Regard 3 as the center of a graph.  Then locate 2 points:  one that is 6 units to the right of 3, and the other that is 6 units to the left of 3.  The final graph consists of just two points:  -3 and 9.  Note that -3 + 6 = 3 (the center) and that 9-6 = 3 (also the center).

Shalnov [3]3 years ago
6 0

|x - 3| - 1 = 5

x - 3 - 1 = 5

x - 4 = 5

x = 9

-(x - 3) - 1 = 5

-x + 3 - 1 = 5

-x + 2 = 5

-x = 3

x = - 3

x = -3 , 9 matched the answers on the number line

Answer is B) |x - 3| - 1 = 5

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Step-by-step explanation:

See explanation

Step-by-step explanation:

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Step-by-step explanation:

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Find the area of a regular pentagon with apothem length of about 10.3 meters. Round to the nearest tenth if necessary.
matrenka [14]

Answer:

The area = 182.52 sq units.

Step-by-step explanation:

  1. Area of regular polygon can be found by splitting into smaller triangles.
  2. Each triangle has base as side of polygon and vertex as center of polygon.

now consider ΔOAB,

we know ∠AOB = \frac{360}{5}° =72°

<h3>     (this is due to symmetry)</h3>

as  ∠AOD = (∠AOB)/2 = 36°

Now we know AD=AB/2 =\frac{10.3}{2} =5.15 m

using trignometric relation tan(∠AOD) =\frac{AD}{OD}

⇒OD = \frac{AD}{tan(36)} = \frac{5.15}{tan(36)}

AREA OF TRIANGLE = BASE × HEIGHT /2

area of ΔOAD = \frac{1}{2} × 5.15 × \frac{5.15}{tan(36)}

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<u>As there are 10 such triangles like </u>ΔOAD

Total area =10×\frac{(5.15)^2}{2tan(36)}

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4 0
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To verify the associative property of addition, begin
Marta_Voda [28]

The sum of the given polynomial is 5x²- 5x +9

<h3>Sum of polynomial</h3>

Polynomials are expressions with a degree of 3 and above. Given the equation shown;

(3x + 4) + ((5x²-1) + (2x + 6))

Expand

(3x + 4) + ((5x²-1) + (2x + 6))

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Collect the like terms

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Hence the sum of the given polynomial is 5x²- 5x +9

Learn more on polynomial here; brainly.com/question/2833285

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