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3 years ago

A clock loses 5 minutes every day. how much time will it lose in 2 hours?

1 answer:

3 0

If a clock loses 5 minutes every day that means it loses 5 minutes every 24 hours. the question askes us how much it will lose in 2 hours. hours have a ratio of 12:1 so will minutes will have 5 /12 = 0.416.
it will loose 0.416 min so it will lose 25 seconds

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An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir

Serhud [2]

Answer:

The artist used $8.6\ in$ more of silver wire

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

we know that

The Perimeter of the square is equal to

$P=4a$

where

a is the length side of the square

$P=40\ in$

$40=4a$

$a=10\ in$

Each side of the square has a length of 10 in

step 2

Find the circumference of the circle

The diameter of the circle is equal to the length of the side of the square

The circumference is equal to

$C=\pi D$

we have

$D=10\ in$

substitute

$C=(3.14)(10)=31.4\ in$

step 3

Find the difference

$40\ in-31.4\ in=8.6\ in$

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3 years ago

B = 54°, b=15, c=<br> c = ? (Round answers to<br> the nearest hundredth.)

zaharov [31]

Answer:

18.54

Step-by-step explanation:

sine is opposite/hypotenuse, and you have opposite (b=15), so use that

sin(54) = 15/c

c = 15/sin54

then use calculator

c = 18.54

8 0

2 years ago

Mean Value theorem help! BRAINLIEST if you can explain it clearly!!!

Korolek [52]

$\bf f(x)=ln(x-5)\qquad [6,8]\qquad \cfrac{df}{dx}=\cfrac{1}{x-5}\\\\
-----------------------------\\\\
\textit{mean value theorem}\qquad f'(c)=\cfrac{f(b)-f(a)}{b-a}\\\\
-----------------------------\\\\
f'(c)=\cfrac{1}{c-5}\qquad thus\quad \cfrac{1}{c-5}=\cfrac{f(8)-f(6)}{8-6}
\\\\\\
\cfrac{1}{c-5}=\cfrac{ln(3)-ln(1)}{2}\implies \cfrac{1}{c-5}=\cfrac{ln(3)-0}{2}
\\\\\\
\cfrac{2}{ln(3)}=c-5\implies \boxed{\cfrac{2}{ln(3)}+5=c}$

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3 years ago

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Mariana [72]

Your Answer should be True

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dezoksy [38]

Take a look at the photo attached.

8 0

3 years ago