1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slava [35]
3 years ago
12

What’s the best answer?

Mathematics
1 answer:
kow [346]3 years ago
5 0
I think the last one

You might be interested in
A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population
Wewaii [24]

Answer:

The population size after seven days will be 171.

Step-by-step explanation:

The population of protozoa can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population after t days, Q(0) is the initial population and r is the growth rate.

In this problem, we have that:

Q(0) = 6, r = 0.6137

So

Q(t) = 6(1.6137)^{t}

Find the population size after seven days.

This is Q(7).

Q(7) = 6(1.6137)^{7} = 171

The population size after seven days will be 171.

7 0
3 years ago
A toll road company has two plans for customers. One plan charges $10 per month for rental of a transponder (a box that identifi
Lunna [17]

Answer:

The minimum number of miles you would need to drive in a month to make the first deal a better deal is 66.6 miles.

Step-by-step explanation:

For the first deal to be a better deal it has to cost less than the second plan and you can write an equation in which the first plan has a lower cost than the second one:

10+0.60m<0.75m, where:

m is the number of miles driven

Now, you can solve for m:

10<0.75m-0.60m

10<0.15m

10/0.15<m

m>66.6

According to this, the answer is that the minimum number of miles you would need to drive in a month to make the first deal a better deal is 66.6 miles.

5 0
3 years ago
F(x) = x squared - 3x -7 Find f(-3)
Vladimir [108]

Answer:

11

Step-by-step explanation:

Kgzkgxtkd

bdmgjsitsitktitziiarit

Please ignore the random characters above

Glad to help you =)

4 0
3 years ago
Solve for x<br> 2(3x-4)=4(1/2x-8)
Leona [35]

Answer:

x = -6

Step-by-step explanation:

Solve for x:

2 (3 x - 4) = 4 (x/2 - 8)

Put each term in x/2 - 8 over the common denominator 2: x/2 - 8 = x/2 - 16/2:

2 (3 x - 4) = 4 x/2 - 16/2

x/2 - 16/2 = (x - 16)/2:

2 (3 x - 4) = 4 (x - 16)/2

4/2 = (2×2)/2 = 2:

2 (3 x - 4) = 2 (x - 16)

Divide both sides by 2:

3 x - 4 = x - 16

Subtract x from both sides:

(3 x - x) - 4 = (x - x) - 16

3 x - x = 2 x:

2 x - 4 = (x - x) - 16

x - x = 0:

2 x - 4 = -16

Add 4 to both sides:

2 x + (4 - 4) = 4 - 16

4 - 4 = 0:

2 x = 4 - 16

4 - 16 = -12:

2 x = -12

Divide both sides of 2 x = -12 by 2:

(2 x)/2 = (-12)/2

2/2 = 1:

x = (-12)/2

The gcd of -12 and 2 is 2, so (-12)/2 = (2 (-6))/(2×1) = 2/2×-6 = -6:

Answer: x = -6

7 0
4 years ago
Para responder a questão a,é possível que você tenha pensado em organizar uma tabela de dupla entrada. Cão não tenha feito isso,
love history [14]

Answer:

translation?

Step-by-step explanation:

8 0
3 years ago
Other questions:
  • What is the measure of ∠E? Enter the correct value. Do not enter the degree symbol.
    5·2 answers
  • If A is the area of a circle with radius r and the circle expands as time passes, find dA/dt in terms of dx/dt
    10·1 answer
  • Solve for x x-23=17 NEED TO KNOW FAST PLEASE!!!!
    15·2 answers
  • MATH IN BIOLOGY
    11·1 answer
  • A truck travels beneath an airplane that is moving 160 km/h at an angle of 54.0 ◦ to the ground. How fast must the truck travel
    9·1 answer
  • 10. (01.05)
    12·2 answers
  • Find the cost price when,<br>(a) Selling price = Rs 725 and 15% gain​
    7·1 answer
  • Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
    6·1 answer
  • Plz help!!! ASAP!!!<br><br> -10 pts<br><br> also explain answer <br><br> thx &lt;3
    12·1 answer
  • Help pls ill mark brainlist and follow u
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!