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slava [35]
3 years ago
12

What’s the best answer?

Mathematics
1 answer:
kow [346]3 years ago
5 0
I think the last one

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WILLGIVE A BRAINLEST!!!!
Kryger [21]
A it's A aaaaaaaaej diwm
8 0
3 years ago
Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.
Verdich [7]

Answer:

6x ≥ 3 + 4(2x - 1)

⇔ 6x ≥ 3 + 8x - 4        => remove the parentheses

⇔ 6x - 8x ≥ 3 - 4

⇔ -2x ≥ -1

⇔ 2x ≤ 1 (or 1 ≥ 2x)

⇔ x ≤ 1/2

⇔ x ≤ 0.5

The answer for the question should be:

1 ≥ 2x

6x ≥ 3 + 8x – 4

and the first graph.

6 0
3 years ago
Read 2 more answers
Write two different rational functions whose graphs have the same end behaviour as the graph of y=3x^2
baherus [9]

Answer:

               y=x^2+5x+20\\ \\ y=8x^2+35

Explanation:

The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.

Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.

The limits of the quadratic function of general form y=ax^2+bx+c as x approaches negative infinity or infinity, when a  is positive, are infinity.

That is because as the absolute value of x gets bigger y becomes bigger too.

In mathematical symbols, that is:

\lim_{x \to -\infty}3x^2=\infty\\ \\ \lim_{x \to \infty}3x^2=\infty

Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².

Two examples are:

         y=x^2+5x+20\\ \\ y=8x^2+35

5 0
3 years ago
PLEASE HELP !! WILL GIVE BRAINLIEST 20 POINTS
REY [17]

Answer:

use desmos to figure it out.

5 0
3 years ago
The perimeter of a rectangle is 100 yd. if its width is four times its length, what is the area?
7nadin3 [17]

<span>Length = l</span>

<span>
Width = w</span>

<span>
Perimeter = p = 100

</span>

<span>Perimeter of rectangle = 2(l+w)</span>

<span>
100 = 2 (4w + w)</span>

<span>
100 = 2(5w)</span>

<span>
100 = 10w</span>

<span>
100/10 = w</span>

<span>
10 = w</span>

<span>
w =  10



Area of rectangle = length * width</span>

<span>
a = l*w</span>

<span> a = 4w*w</span>

<span>
a = 4w^2............(1)</span>

<span>
Put the value of w in (1)</span>

<span>
a = 4(10)^2</span>

<span>
a= 4(100)</span>

<span>
a = 400 yd^2</span>

4 0
3 years ago
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