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3 years ago

8

mr. Russell owes 1235 shares of XYZ stock. On Monday, the start decreased by $0.67 a share. On Tuesday, decreased by $0.53 a sha

re. What is the change in the value of stock shares for their two days?

1 answer:

Rus_ich [418]3 years ago

5 0

loss of $1,482.00 is the answer

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A cylindrical oil drum has a diameter of 2 feet and a height of 3 feet what is the volume of the oil drum?

NikAS [45]

We know, Volume of a Cylinder = πr²h

Here, r = 2/2 = 1 ft
h = 3 ft

Substitute their values,
v = 3.14 * (1)² * 3
v = 9.42 ft³

In short, Your Answer would be: 9.42 Ft³

Hope this helps!

4 0

3 years ago

Can someone help answer the first two?

Murljashka [212]

Answer:

below given!

Step-by-step explanation:

1) mean = (7.4 + 5.8 + 7.3 + 7 + 8.9 + 9.4 + 8.3 + 9.3 + 6.9 + 7.5 + 9 + 5.8 + 5.5 + 8.6 + 9.3 +3.8) / 16

mean = 7.47

5 0

2 years ago

Write the word sentence as an equation. Then solve.

Tresset [83]

Answer:

yes

Step-by-step explanation:

4 0

2 years ago

Reduce 36/45 to lowest terms and write the denominator in the blank.

Firlakuza [10]

Answer:

4/5

Step-by-step explanation:

Step 1:

36/45 = 12/15

Step 2:

12/15 = 4/5

Answer:

4/5

Hope This Helps :)

5 0

3 years ago

Read 2 more answers

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

10 months ago