Select the coordinates of two points on the line y = 8.

Find x so that l || m. Show your work.

Hatshy [7]

Hello,

Answer:

x = 13

Step-by-step explanation:

7x + 5 + 5x + 19 = 180

⇔ 12x + 24 = 180

⇔ 12x = 180 - 24

⇔ 12x = 156

⇔ x = 156/12

⇔ x = 13

6 0

1 year ago

Which numbers make a true statement when placed in the box? 7.902 > Select each correct answer.

Zanzabum

The answer is b, I’m not saying it’s true but just predicting xoxoox

6 0

2 years ago

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What is the center of a circle represented by the equation x92y62102

andreev551 [17]

The center of the circle is (-9, -6).

What is the center of the circle?

A circle's center is the point from which all of the distances to the other points on the circle are equal. The radius of the circle is the measurement at issue.

Here, we have

The equation of a circle is written as:

(x - h)² + (y - k)² = a²

Where (h, k) is the center and a is the radius of the circle.

Where (h, k) is the center and a is the radius of the circle.

(x + 9)² + (y + 6)² = 10² (Given)

From the equation, the center of the circle is (-9, -6)

The radius of the circle is 10.

In general form, the equation can be written as

x² + 18x + 81 + y² + 12y + 36 = 100

x² + y² + 18x + 12y + 17 = 0

Hence, the center of the circle is (-9, -6).

To learn more about the center of the circle from the given link

brainly.com/question/25938130

#SPJ4

8 0

1 year ago

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.

4 0

3 years ago

Solve for the variable. 1) 8 - X-X=-16<br><br><br><br>plsss help me explain me slow

Nady [450]

Step-by-step explanation:

3 0

1 year ago

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