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ira [324]
3 years ago
15

The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

company is worth $40,000 in 1990, how much is it worth in 2000
Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

f'(t)=2000-12t^{2}

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (<em>t</em> = 0) to 2000 (<em>t</em> = 10) as follows:

\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

                        =40000+16000\\=56000

Thus, the worth of the company in 2000 is $56,000.

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Answer:

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Step-by-step explanation:

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We then have a product of x and 6, that x * 6, which we write usually in the format 6x.

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2. The sum of the quantity x- 3 and y  

The sum is an addition.  The sum of a and b is a + b.

In this case, the first part is x - 3, the second part is y

So, x - 3 + y, which we usually rewrite as x + y - 3

3. The quotient of x and z is y

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So, quotient of x and z is x/z.

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4. The difference of 2 and x is p.

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7 0
3 years ago
A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50%50% of this population prefer
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Answer:

0.1527

Step-by-step explanation:

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Suppose that 50% of this population prefers the color red

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Let X be the no of buyers who prefer red.

X has exactly two outcomes red or non red.

Also each buyer is independent of the other

Hence X is binomial with p = 0.5 and n = 15

Required prob =The probability that exactly three-fifths of the buyers would prefer red

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What is the area of this figure?
ludmilkaskok [199]

Answer:

          \large\boxed{\large\boxed{42 unit^2}}

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The figure is not a regular hexagon. It is an irregular hexagon.

Please, find attached the picture with the original question and the figure.

You can split the figure into two triangles and one rectangle.

The rectangle has dimensions: 7units × 4units, thus its area is 28 units².

Both the upper triangle and lower triangle have base 7 units and height 2 units.

Hence the area of each triangle is:

       area=(1/2)base\times height

       

      area=(1/2)7units\times 2units = 7units^2      

Hence, the area of the hexagon is:

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The answer is 120°. Hope it helps.

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